Intermediate Algebra
Answer/Discussion to Practice
Problems
on Rationalizing Denominators
and Numerators
of Radical Expressions
Answer/Discussion
to 1a

|
| Step 1: Multiply numerator and denominator by a radical
that will get rid of the radical in the denominator. |
| Since we have a square root in the denominator, we need to
multiply by the square root of an expression that will give us a perfect
square under the square root in the denominator.
So in this case, we can accomplish this by multiplying top and bottom
by the square root of 11: |
 |
*Mult. num. and den. by sq. root of 11
*Den. now has a perfect square under sq. root
|
| Step 3: Simplify the fraction if needed. |
 |
*Sq. root of 121 is 11
|
Answer/Discussion
to 2a

|
| Step 1: Multiply numerator and denominator by a radical
that will get rid of the radical in the numerator. |
| Since we have a cube root in the numerator, we need to multiply
by the cube root of an expression that will give us a perfect cube under
the cube root in the numerator.
So in this case, we can accomplish this by multiplying top and bottom
by the cube root of : |
 |
*Mult. num. and den. by cube root of
*Num. now has a perfect cube under cube root
|
| Step 3: Simplify the fraction if needed. |
 |
*Cube root of 125 y
cubed is 5y
|
Answer/Discussion
to 3a

|
| Step 1: Find the conjugate of the denominator. |
| In general the conjugate of a + b
is
a
- b and vice versa.
So what would the conjugate of our denominator be?
It looks like the conjugate is . |
| Step 2: Multiply the numerator and the denominator
of the fraction by the conjugate found in Step 1 . |
| Step 4: Simplify the fraction if needed. |
| No simplifying can be done on this problem so the final answer is:

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