Beginning Algebra
Answer/Discussion to Practice Problems
Tutorial 7: Multiplying and Dividing Real Numbers
Answer/Discussion
to 1a
(2)(25) 
(2)(25) = 50.
The product of the absolute values 2 and 25 is 50 and they have the
same sign, so that is how we get the answer 50. 
Answer/Discussion
to 1b
(0)(100) 
Answer/Discussion
to 1c
(2)(3)(5) 
Working it left to right we get: 
(2)(3)(5) =
(6)(5) =
30 

Answer/Discussion
to 2a

(25)/(5) = 5.
The quotient of the absolute values (25)/(5) = 5 and they have opposite
signs, so that is how we get the answer 5. 
Answer/Discussion
to 2b

Answer/Discussion
to 2c


*Div. is the same as mult. by reciprocal
*Mult. num. together
*Mult. den. together
*()() = 
*Reduce fraction 
Answer/Discussion
to 3a


*Evaluate inside the absolute values
*Multiply
*Add
*Reduce fraction

Answer/Discussion
to 4a

Plugging 5 for x and 5 for y and
simplifying we get: 

*Plug in 5 for x and 5 for y
*Exponent
*Multiply
*Subtract

Last revised on July 25, 2011 by Kim Seward.
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