3 Title

Beginning Algebra
Tutorial 13: Multiplication Property of Equality

 *Inverse of mult. by -8 is div. by -8

 If you put -3 back in for a in the original problem you will see that -3 is the solution we are looking for.

 *Inverse of mult. by 2/3 is did. by 2/3  (or mult. by reciprocal 3/2)

 If you put 12 back in for x in the original problem you will see that 12 is the solution we are looking for.

 *Inverse of add 5 is sub. 5 *Inverse of mult. by 6 is div. by 6

 If you put 0 back in for y in the original problem you will see that 0 is the solution we are looking for.

 *Inverse of add 3x is sub. 3x   *Inverse of sub.  3 is add 3   *Inverse of mult. by 2 is div. by 2

 If you put 5 back in for x in the original problem you will see that 5 is the solution we are looking for.

 Answer/Discussion to 2a If x represents the first of three consecutive integers, express the sum of the three integers in terms of x.

First of all, we need to have all three consecutive integers in terms of x

We can represent them the following way:

 x         = 1st integer x + 1   = 2nd consecutive integer x + 2   = 3rd consecutive integer

Second we need to write it as a sum of the three integers and then simplify it:

 *The sum of the three cons. integers *Combine like terms

Last revised on July 26, 2011 by Kim Seward.