Intermediate Algebra
Answer/Discussion to Practice
Problems
on Complex Fractions
Answer/Discussion
to 1a
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| Combining only the numerator we get: |
 |
*Rewrite fractions with LCD of 10
|
| Combining only the denominator we get: |
 |
*Rewrite fractions with LCD of 6
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| Putting these back into the complex fraction we get: |
 |
*Write numerator over denominator |
| Step 2: Divide the numerator by the denominator
by multiplying the numerator by the reciprocal of the denominator
AND
Step 3: If needed, simplify
the rational expression. |
 |
*Rewrite div. as mult. of reciprocal
*Divide out a common factor of 2
|
Answer/Discussion
to 1b
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| Rewriting the expression with positive exponents, we get: |
 |
*Rewrite with positive exponents
|
| The two denominators of the numerator's fractions have the following
factors: |
| The two denominators of the denominator's fractions have the
following factors: |
and  |
|
| Putting all the different factors together and using the highest exponent,
we get the following LCD for all the small fractions: |
| Multiplying numerator and denominator by the LCD we get: |
 |
*Mult. num. and den. by x
squared
y squared
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All contents copyright (C) 2001 - 2008, WTAMU and Kim Seward. All rights reserved. Last revised on Jan. 8, 2002 by Kim Seward. |