Intermediate Algebra
Answer/Discussion to Practice
Problems
on Multiplying and Dividing
Rational Functions
 Answer/Discussion
to 1a
Our restriction here is that the denominator of a fraction can never
be equal to 0. So to find our domain, we want to set the denominator
"not equal" to 0 to restrict those values. |
 |
*Restrict values that cause den. to be 0
*"Solve" for x
*"Solve" for x
|
| Our domain is all real numbers except -5 and 5 because they
both make the denominator equal to 0, which would not give us a real number
answer for our function.
(return to
problem 1a) |
| Answer/Discussion
to 2a
|
 |
*Factor the num. and den.
*Divide out the common factors
of (2x + 1), (2x
- 1), and (3x + 2)
|
| Answer/Discussion
to 2b
|
 |
*Rewrite as mult. of reciprocal
*Factor the num. and den.
*Div. out the common factors of
(2x + 3), (x
-
4), and (2x + 1) |
| Answer/Discussion
to 2c
|
 |
*Rewrite the div. as mult. of recip.
*Factor the num. and den.
*Div. out the common factors of
(b - 4), (b
- 4), (b - 5), and (b
- 3) |
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Last revised on Jan. 8, 2002 by Kim Seward. |
