College Algebra Tutorial 36


College Algebra
Answer/Discussion to Practice Problems  
Tutorial 36:Long Division



WTAMU > Virtual Math Lab > College Algebra > Tutorial 36: Long Division


 

checkAnswer/Discussion to 1a

problem 1a
 

Step 1: Set up the long division.

 
ad1a1
*Write in descending order

 
 
Step 2:  Divide 1st term of dividend by first term of divisor to get first term of the quotient.

 
Note that the "scratch work" that you see at the right of the long division shows you how that step is filled in.  It shows you the "behind the scenes" of how each part comes about. 

 
ad1a3
Scratch work:
ad1a2

 
Step 3:  Take the term found in step 2 and multiply it times the divisor.

 
ad1a5
Scratch work:
ad1a4

 
 
Step 4:  Subtract this from the line above.

 
ad1a7
Scratch work:
ad1a6

 
 
Step 5:  Repeat until done.

 
We keep going until we can not divide anymore. 

We just follow the the same steps 2 - 4 as shown above.  Our "new dividend" is always going to be the last line that was found in step 4.
 

Step 2 (repeated): Divide 1st term of dividend by first term of divisor to get next term of the quotient.

AND
 

Step 3 (repeated): Take the term found in step 2 and multiply it times the divisor.

AND
 

Step 4 (repeated): Subtract this from the line above.

 
The following is the scratch work (or behind the scenes if you will) for the rest of the problem.  You can see everything put together following the scratch work under "putting it all together".  This is just to show you how the different pieces came about in the final answer.  When you work a problem like this, you don't necessarily have to write it out like this.  You can have it look like the final product shown after this scratch work.

 
Scratch work for steps 2, 3, and 4
for the last two terms of the quotient

2nd term:
ad1a8

ad1a10

ad1a11
 

3rd term:
ad1a9

ad1a12

ad1a13
 

Putting it all together:

Note that each second line is SUBTRACTED, so the line shows what the signs of each term would be when you subtract it. 
 

ad1a14
 
 

Step 6: Write out the answer.

 
ad1a15
*Quotient with a remainder of -32

 
(return to problem 1a)


 

checkAnswer/Discussion to 1b

problem 1b
 

Step 1: Set up the long division.

 
ad1b1
*Write in descending order
*Insert 0's for missing terms

 
 
Step 2:  Divide 1st term of dividend by first term of divisor to get first term of the quotient.

 
Note that the "scratch work" that you see at the right of the long division shows you how that step is filled in.  It shows you the "behind the scenes" of how each part comes about. 

 
ad1b3
Scratch work:
ad1b2

 
Step 3:  Take the term found in step 2 and multiply it times the divisor.

 
ad1b5
Scratch work:
ad1b4

 
 
Step 4:  Subtract this from the line above.

 
ad1b7
Scratch work:
ad1b6

 
 
Step 5:  Repeat until done.

 
We keep going until we can not divide anymore. 

We just follow the the same steps 2 - 4 as shown above.  Our "new dividend" is always going to be the last line that was found in step 4.
 

Step 2 (repeated): Divide 1st term of dividend by first term of divisor to get next term of the quotient.

AND
 

Step 3 (repeated): Take the term found in step 2 and multiply it times the divisor.

AND
 

Step 4 (repeated): Subtract this from the line above.

 
The following is the scratch work (or behind the scenes if you will) for the rest of the problem.  You can see everything put together following the scratch work under "putting it all together".  This is just to show you how the different pieces came about in the final answer.  When you work a problem like this, you don't necessarily have to write it out like this.  You can have it look like the final product shown after this scratch work.

 
Scratch work for steps 2, 3, and 4
for the last three terms of the quotient

2nd term:
ad1b8

ad1b11

ad1b12
 

3rd term:
ad1b9

ad1b13

ad1b14
 

4th term:
ad1b10

ad1b15

ad1b16
 

Putting it all together:

Note that each second line is SUBTRACTED, so the line shows what the signs of each term would be when you subtract it. 
 

ad1b17
 
 

Step 6: Write out the answer.

 
ad1b18
*Quotient with no remainder
 
(return to problem 1b)

 

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WTAMU > Virtual Math Lab > College Algebra >Tutorial 36: Long Division


Last revised on March 15, 2010 by Kim Seward.
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