*Standard form of quad. function
If you said (- 4, -2) you are correct.
Be careful about your signs on this problem. Notice how the sign
in front of h is a minus, but the one in front
of k is positive. So h is the number we are subtracting from x, which
in our case is negative 4. k is the number
we are adding at the end, which our case we are adding a negative 2.
If we know which direction the curve opens, that can help us answer this question.
Since a = -1, and -1 is less than 0, this parabola would open down .
So does that mean the vertex is a maximum or minimum point?
If you said a maximum point, you are right on.
So our vertex (- 4, -2) is the maximum point.
*Identify a, b,
and c
*Plug values into vertex form. for a, b,
and c
*Plug 1 in for x to find the y value of the vertex
If we know which direction the curve opens, that can help us answer this question.
Since a = 1, and 1 is greater than 0, this parabola would open up .
So does that mean the vertex is a maximum or minimum point?
If you said a minimum point, you are right on.
So our vertex (1, 1) is the minimum point.
This gives us a good reference to know we are going in the right direction.
If you said (-2, 1) you are correct.
Be careful about your signs on this problem. Notice how
the sign in front of h is a minus, but the
one in front of k is positive. So h is
the number we are subtracting from x, which
in our case is -2. k is the number we
are adding at the end, which our case we are adding a 1.
x-intercept
Reminder that the x-intercept is always
where the graph crosses the x-axis which means y = 0:
*Plug in values for a, b,
and c
This gives us a good reference to know we are going in the right direction.
*Identify a, b,
and c
*Plug values into vertex form. for a, b,
and c
*Plug 0 in for x to find the y value of the vertex
x-intercept
Reminder that the x-intercept is always
where the graph crosses the x-axis which means y = 0:
*Solve
the quadratic by factoring
Last revised on July 10, 2010 by Kim Seward.
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