Beginning Algebra
Answer/Discussion to Practice Problems
Tutorial 21: Graphing Linear Equations
Answer/Discussion
to 1a
y = 2x  1 
If we subtract 2x from both sides, then
we can write the given equation as 2x + y = 1.
Since we can write it in the standard form, Ax + By = C, then we have a linear equation.
(return to problem
1a) 
Answer/Discussion
to 1b

If we add x squared to both sides we would
end up with .
Is this a linear equation? Note how we have an x squared
as opposed to x to the one power.
It looks like we cannot write it in the form Ax + By = C, because the x has to be to the one power, not squared. So this is not a linear
equation.
(return to problem
1b) 
Answer/Discussion
to 2a
y = 2x  1 
The three x values I'm going to use are
1, 0, and 1. (Note that you can pick ANY three x values that
you want. You do not have to use the values that I picked.) You
want to keep it as simple as possible. The following is the chart
I ended up with after plugging in the values I mentioned for x.
x

y = 2x 
1

(x, y)

1

y = 2(1)  1 = 3

(1, 3)

0

y = 2(0)  1 = 1

(0, 1)

1

y = 2(1)  1 = 1

(1, 1)


Answer/Discussion
to 2b

The three x values I'm going to use are
1, 0, and 1. (Note that you can pick ANY three x values that
you want. You do not have to use the values that I picked.) You
want to keep it as simple as possible. The following is the chart
I ended up with after plugging in the values I mentioned for x.
x

y = 1/2x

(x, y)

1

y = 1/2(1) = 1/2

(1, 1/2)

0

y = 1/2(0) = 0

(0, 0)

1

y = 1/2(1) = 1/2

(1, 1/2)


Last revised on July 29, 2011 by Kim Seward.
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